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1 . if I want to compress 22.4 Litres of Oxygen gas at N.T.P. ( one mole i.e. 32 gm) to say 20 atmospq. pressure
how much energy will be consumed in doing that.
Also if I want to compress Hydrogen (without liquification) what will be the enegy required ( from 22.4 ltrs at N.T.P. to 20 atm pressure.
2. How much thick Steel cylinder is required sustain this much pressure ( 20 atm) What will be the weight of steel cylinder which can contain 22.4 ltrs of original oxygen compressed to 20 atm.
3.
Relation between one atmossperic pressure to onr bar pressure or one PSI pressure

2007-03-28 10:05:35 · 1 answers · asked by mahesh asker 1 in Science & Mathematics Engineering

1 answers

The work done on the gas is the definite integral (PdV) that is the energy consumed. Power is work/unit time.

The cylinder thickness can be determined by looking at the hoop stress generated by the pressure inside. That stress is equal to the diameter of the cylinder x the pressure divided by the wall thickness. The larger the diameter the thicker the wall will have to be. I'm not up on pressure vessell codes but the stress limits should be published somewhere.

1 atmosphere = 1 bar 1 atmosphere = 14.7 lbs/in^2

Don't try this at home. Pressure vessels containing gases can violently explode. 20 bar is going to be around 300 psi and is well above the rating of most compressed air tanks. Also pressurized oxygen can also cause explosions if there are any combustable contaminants in the vessel.

2007-03-28 14:59:05 · answer #1 · answered by Roadkill 6 · 0 0

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