physics please help?

0 ⤊

physics please help?

A 9500-pF capacitor holds plus and minus charges of 16.5 x 10^ -8 C. What is the voltage across the capacitor?

2007-03-28 06:58:06 · 2 answers · asked by vtchick1441 1 in Science & Mathematics ➔ Engineering

2 answers

The capacitor's capacitance (C) is a measure of the amount of charge (Q) stored on each plate for a given potential difference or voltage (V) which appears between the plates:

C=Q/V
where C is in coulombs
Q is in Farads (pico is 10E-12)
V is in volts
so V=Q/C=16.5E-8/.0000000095=17.4 volts
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2007-03-28 08:27:38 · answer #1 · answered by SWH 6 · 0⤊ 0⤋

Your going to need to do the integral.
1/C*intntegral

2007-03-28 07:21:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋