I thought my flight computer would calculate this, but I'm having a hard time figuring out the answer.
How do you solve for something like this?
2007-03-27 06:08:21 · 7 answers · asked by Sapphire Orb 1 in Cars & Transportation ➔ Aircraft
It's approximately your TAS minus 1/2 your altitude divided by 100.
So 470-(18000/100), then 470-180= 290. This is based on no winds, which you are probably aware of.
2007-03-27 07:55:49 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Found this link, http://www.airliners.net/discussions/tech_ops/read.main/131373/
The 3rd post in link above gives best explanation and an example, but you'll have to reverse the math.
Huckelberry is probably pretty darn close, the plane I fly on, we usually are doing about 270 kts IAS and about 420 TAS at FL290. I take it the -63(c) is in SAT?
2007-03-27 07:57:33 · answer #2 · answered by sc0tt.rm 3 · 1⤊ 0⤋
39,000 MSL, -63º C and TAS of 470 kts, I got on my E6B 243 kts CAS, which would also be your IAS in this case.
2007-03-27 14:33:43 · answer #3 · answered by Timothy B 4 · 0⤊ 2⤋
E6B shows approx. 265 kts.
2007-03-27 08:52:39 · answer #4 · answered by Anonymous · 0⤊ 1⤋
264 KIAS would give you 469.92 TAS at 39,000 feet.
2007-03-27 09:21:00 · answer #5 · answered by Chris H 6 · 0⤊ 2⤋
i think it's probably around 280-290kts.
2007-03-27 07:29:13 · answer #6 · answered by huckleberry58 4 · 0⤊ 0⤋
you going to run out of fuel..
2007-03-27 13:33:04 · answer #7 · answered by eviot44 5 · 0⤊ 3⤋