2007-03-26 17:05:00 · 7 answers · asked by sparklycrayons 1 in Science & Mathematics ➔ Engineering
What's i^-25?
2007-03-26 17:05:21 · update #1
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
These repeat for every multiple of 4.
So i^24 is 1, and i^25 has to be the next one in the cycle which is i. The negative sign with the exponent just moves it to the denominator.
i^-25 = 1/i
2007-03-26 17:11:24 · answer #1 · answered by ecolink 7 · 1⤊ 0⤋
i^-25 = 1/i^25
= 1/(i^24 x i^1)
= 1/(1 x i)
= 1/i or i^-1
2007-03-27 00:20:05 · answer #2 · answered by bob b 3 · 0⤊ 0⤋
i^-25=i^-1=-i
2007-03-27 00:13:09 · answer #3 · answered by JAMES 4 · 0⤊ 0⤋
negative exponents mean to change location either from top to bottom or bottom to top
since it is currently in the top, make it 1/i^25 then simplify
2007-03-27 00:10:20 · answer #4 · answered by enderbean 3 · 0⤊ 0⤋
Any nonzero number raised to a negative power equals its reciprocal raised to the opposite positive power.
2007-03-27 00:13:16 · answer #5 · answered by nickscalero 2 · 0⤊ 0⤋
i to any odd negative power is just -i. If i is at a negative even power, it is 1.
-i * -i * -1 = -i
-i * -i = 1
2007-03-27 11:39:11 · answer #6 · answered by joshnya68 4 · 0⤊ 0⤋
i^-25 = 1 / (i^25);
i^25 = i² = (â-1)² = -1
So, i^-25 = 1 / (i²) = 1 / (-1) = -1
Q.E.D.
2007-03-27 00:10:06 · answer #7 · answered by Esse Est Percipi 4 · 0⤊ 0⤋