A sinlge phase AC motor is needed to lift up vertically a load of 150kg to 200kg using chain and gear. Please help.
2007-03-26 16:27:52 · 2 answers · asked by Martin 1 in Science & Mathematics ➔ Engineering
a SINGLE PHASE MOTOR to lift up vertically 150kg. time is 5 seconds and height is about 12 feet
2007-03-26 16:45:38 · update #1
You have mixed units, so I will first convert your 12 feet to meters.
12 ft * 12 in / ft * .0254 m / in = 3.66 meters
Power = work / time = (force * distance) / time
Work = force * distance
Force = mass * g
Power = (mass * g * distance) / time
Power = (150 kg * 9.8 m/sec^2 * 3.66 m) / 5 sec = 1076 N-m/sec
The units "N-m/sec" can also be expressed as a watt (W). 1076 watts
1 HP = 746 watts.
1076 watts * 1 HP / 746 watts = 1.44 HP
Since you cannot purchase a 1.44 HP motor, we’ll round this up to 1½ HP.
Repeating these steps for 200 kg results in a 2 HP motor.
2007-03-26 16:34:58 · answer #1 · answered by Thomas C 6 · 0⤊ 0⤋
ditto
2007-03-27 16:47:53 · answer #2 · answered by heartsave999 2 · 0⤊ 0⤋