English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I'm having trouble understanding this question and the method to do it.


A rider is thrown out of a horse and sulky. The horse continues to pull with a force of 20000N. The sulky has mass of 100kg. The rider has a mass of 60kg, is hanging on to the back of the sulky dragging on the ground. Friction forces total 19,200N.
Determine the acceleration of the sulky.

Please help.

It will be appreciated.

2007-03-25 23:31:06 · 2 answers · asked by Hmmmmm 3 in Science & Mathematics Physics

2 answers

First you have a net pulling force of-:
20,000 - 19,200 = 800 Newtons

Then use F = ma

Net Force = Total Mass x Acceleration
800 = (100 + 60) x a

800 / 160 = 5 ms^-2

2007-03-25 23:35:25 · answer #1 · answered by Doctor Q 6 · 0 0

F=ma
A=F/m
F=20,000N-19,200N
m=100kg +60kg

I'll leave you to do the math

2007-03-26 06:36:18 · answer #2 · answered by Justin H 4 · 0 0

fedest.com, questions and answers