2007-03-25 20:11:43 · 4 answers · asked by Dung N 1 in Science & Mathematics ➔ Mathematics
the answer for this is....
it has an imaginary root...
by using the quadratic formula
-b (+-) sqrt(b^1 -4a) / 2a
you will get the following answer
x= [2 + sqrt(26)*(i)]/10 and
x= [2 - sqrt(26)*(i)]/10
hope this will help
2007-03-25 20:22:04 · answer #1 · answered by Anime Lover 3 · 0⤊ 0⤋
Assume question of:-
10x² - 4x - 3 = 0
x = [4 ± â (16 + 120)] / 20
x = [4 ± â136] / 20
x = [ 4 ± 2â 34] / 20
x = [2 ± â34] / 10
x = 0.78, x = - 0.38
2007-03-26 03:32:43 · answer #2 · answered by Como 7 · 0⤊ 0⤋
if you mean 10x^2-4x+3=0, thie equation has no answer in real number world, but if you mean 10x^2-4x-3=0, it has two answers, you can solve it like this:
find the Delta=(-4)^2-4(10)(-3)=136,
assume k=Delta^(1/2)=136^(1/2)
then the roots are:
x1=[-(-3)+k]/(2*10)
x2=[-(-3)-k]/(2*10)
2007-03-26 03:47:48 · answer #3 · answered by raheleh 2 · 0⤊ 0⤋
dont know if the first = is a + or a -
2007-03-26 03:15:29 · answer #4 · answered by PenquinZ 1 · 0⤊ 0⤋