See g(x) = √(x - 2)
Now √(x - 2) cannot be negative as then the function would become imaginary. The minimum value must be zero.
If x = 2, x - 2 = 0
Since any value of x lower than x = 2, makes x - 2 negative and in turn renders √(x - 2) imaginary, x cannot be any value lesser than 2. All values from 2 to positive infinity are applicable for g(x). It applies to f(x) too. Considering f(x), x can be anything, but in order for a set of values to satisfy both functions, [2,∞ ] is the solution.
2007-03-25 19:44:19
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answer #1
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answered by Akilesh - Internet Undertaker 7
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The domain of the quotient is going to be the intersection of the domain of f, and the subset of the domain of g for which g(x) ≠ 0. Now the domain of f is all of R, the domain of g is [2, ∞) and g(x) = 0 at x = 2. So the domain of f/g is (2, ∞).
Note: it is not [2, ∞), much less [2, ∞] which doesn't even translate to a valid interval since ∞ is not a real number.
2007-03-25 19:40:31
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answer #2
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answered by Scarlet Manuka 7
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Ok here we go. I assume that you know that you have to turn that into a fraction. After that you have to multiply both top and bottom by the denominator because you cannot have a squareroot on the bottom of a fraction. When you do that you x-2 at the bottom. to find the domain you have to set the denominator equal to zero. Therefore you get x=2. I would not include the 2 because it would make the problem undefined. So I would write my answer as (2, infinity].
2007-03-25 19:45:58
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answer #3
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answered by Kristian 2
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They probably want you to stay with real numbers, which would require that x-2 be nonnegative since you're taking the square root of that quantity. Therefore, x would have to be in the range [2, inf] to avoid imaginary numbers.
2007-03-25 19:42:02
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answer #4
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answered by M T 2
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since f/g gives you (x - 3)/(sqrt(x - 2))
the dominator can't be 0 and you can't have a negative in the sqrt, the only possible values are greater than 2, so the answer would be (2,∞)
2007-03-25 21:10:35
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answer #5
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answered by Sherman81 6
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Domain of f/g will be:
►D(f/g) =[ Df Π Dg ] - { x | g(x)=0 }
so Df= R
Dg = [ 2 ,∞)
Df Π Dg - {x | g(x)=0 } = [ R Π [ 2 ,∞) ] - {2} =
► D(f/g) = ( 2, ∞)
hope this helps
2007-03-25 19:47:51
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answer #6
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answered by arman.post 3
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