One number is 8 less than another.If 5 times the smaller number minus 2 times the larger number is14,find 2 #s

Question

Find the two numbers?

Answer 1

y = x - 8
5y - 2x = 14

5(x - 8) - 2x = 14
5x - 40 - 2x = 14
3x = 54
x = 18

y = 18 - 8
y = 10

ANS : 18 and 10

Answer 2

let one number be x
therefore another number would be x-8
according to given information,
5(x-8) - 2(x) = 14
5x -40 -2x = 14
3x = 14 + 40
3x = 54
x = 18
x-8 = 10

therefore two nos are 10 and 18..

Answer 3

x = 1st number
x + 8 = 2nd number

5x - 2(x + 8) = 14
5x -2x -16 =14
3x -16 = 14
3x = 30
x = 10
x + 8 = 18

The one number is 10 and the other is 18.

Answer 4

1st number = x
2nd number = x - 8

5(x-8) - 2x = 14
5x - 40 - 2x = 14
3x - 40 = 14
3x = 54
x = 18
x - 8 = 10

The two numbers are 18 and 10.

Answer 5

First, create two variables, x and y.

Let x = the smaller number and y = the larger number.

From the question, you get two equations:
x = y - 8
5x - 2y = 14

You can solve the problem using substitution.

5(y-8) - 2y = 14
5y - 40 - 2y = 14
3y = 54
y = 18

x = 18 - 8 = 10

The two numbers are 10 and 18.

Answer 6

x= (-8) + y
5x - 2y = 14

substitute to find y

5(-8 + y) - 2y = 14
-40 + 5y - 2y = 14
-40 + 3y = 14
3y = 54
3y / 3 = 54 / 3
y = 18

now redo both problems to solve for x, cause now you know y

x= (-8) + 18
x = 10

5x - 2(18) = 14
5x - 36 = 14
5x = 50
5x / 5 = 50 / 5
x = 10

you solve for both to make sure you dont screw up.

x=10, y =18