How would you prepare 250mL of a 0.150M solution of CoCl2 from solid CoCl2 and distilled water?

Question

k=slope=0.46 (I don't know if we need the slope to do this by the way) please help, I have no idea how to do this.

Answer 1

Atomic weights: Co=59 Cl=35.5 CoCl2=130 Let CoCl2 solution be called S.

250mLS x 0.150molCoCl2/1000mLS x 130gCoCl2/1molCoCl2 = (250)(0.150)(130)/(1000) = 4.88gCoCl2