What is the net torque acting on the cylinder about the rotation axis?

Question

A one-piece cylinder is shaped as in the figure below, with a core section protruding from the larger drum. The cylinder is free to rotate around the central axis shown in the drawing.
A rope wrapped around the drum, of radius 1.38 m, exerts a force F1 to the right on the cylinder. A rope wrapped around the core, of radius 0.465 m, exerts a force F2 downward
on the cylinder.
Let F1 = 4.42 N and F2 = 7.37 N.

What is the net torque acting on the cylinder about the rotation axis (which is the z axis in the figure)? Answer in units of Nm

Answer 1

You seem to have the directions of action a bit mixed up here.
Torque or Moment is given by:

T = r x F metreNewtons

Work the Torques out for the two forces and then either add or subtract them to get the total!

NOTE: Torques are axial vectors. They add like vectors so if the torques are no in the same direction draw a vector addition diagram.

Answer 2

i do no longer think of they are performing interior the comparable course. that is hard to visualise, yet i think of the tension to the the excellent option may be around the rotational axis = a million.32*3.80 5 Nm = 5.082 Nm. The tension exerted downwards is at suitable angles to the rotational axis and would not make a contribution to the torque performing regarding the rotational axis. counting on the orientation of the cylinder, it ought to be any incorrect way around. If the cylinder is horizontal, down is around the rotational axis. If the cylinder is vertical, down isn't around the rotational axis.