Chem Problems?

Question

1. A gas has a volume of 300.0 mL at a pressure of 740 mm Hg. Calculate its volume if its pressure quadruples at a constant temperature and mols.

2. A sample of Helium has a volume of 35.0 mL at 1.25 atm. If the helium is compressed to a volume of 10.0 mL at constant temperature, what is the new pressure of the helium gas?

Answer 1

both involve boyles law, PV=PV

1) 300 x 740 = 2960 x X (740 x 4=2960, they said the pressure quarduples.)

X= 75 mL

2) 35.0 x 1.25 = 10.0 x X

X= 4.375 atm

Answer 2

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Answer 3

Both problems can be solved using Boyle's law (P1V1=P2V2).
For 1. P1=740mmHg; V1=300.0mL; P2=4x740.0mmHg
Substituting these values on the equation gives V2 of 75.0mL

For 2. P1=1.25atm; V1=35.0mL; V2=10.0mL
Substituting these to the equation gives P2 of 4.38atm (notice the proper number of significant digits on the final answer).