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Suppose that gene "b" is sex-linked, recessive and lethal. A man marries a woman who is heterozygous for this gene. If this couple had many normal children, what would be the projected sex ratio of the children?

2007-03-25 12:47:18 · 4 answers · asked by Anonymous in Science & Mathematics Biology

4 answers

It may be 2 girls: 1 boy because the Punnett square for this cross would show 2 normal girls: 1 normal boy: 1 affected boy. Since they had many normal children, then they didn't get any of the affected boys. That leaves 2 girls: 1 boy.

2007-03-25 12:51:35 · answer #1 · answered by ecolink 7 · 0 0

If the gene was sex-linked and lethal, then statistically, half of the male children should die. That would leave you with a ratio of 2 girls to 1 boy.

2007-03-25 12:55:49 · answer #2 · answered by JazzSinger 6 · 0 0

they would probably have more girls than boys
possible 2 girls and 1 boy I think

I guess the gene must be one the X chromosome, so the girls would have 2 chances not to get the gene (because they have 2 chromosomes, and one is used as a barr body) and the boys they had must have gotten lucky and received mom's dominant X chromosome

2007-03-25 12:52:05 · answer #3 · answered by Anonymous · 0 0

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2016-12-19 13:49:06 · answer #4 · answered by ? 4 · 0 0

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