Magnetism Question Part 4?

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Magnetism Question Part 4?

A 0.45-m copper rod with a mass of 0.17kg carries a current of 11A in the positive x direction. What are the magnitude and direction of the minimum magnetic field needed to levitate the rod?

2007-03-25 11:33:13 · 1 answers · asked by bigpapamarek 1 in Science & Mathematics ➔ Physics

1 answers

F = BIL, force of the magnetic field on the rod must equal the rod's weight for levitation to occur.

2007-03-25 11:36:32 · answer #1 · answered by msi_cord 7 · 0⤊ 0⤋