Magnetism Question?

0 ⤊

A 0.32-uC particle moves with a speed of 16m/s through a region where the magnetic field has a strength of 0.95T. At what angle to the field is the particle moving if the force exerted on it is 4.8x10^-6N.

Can someone just show me the formula to use.

2007-03-25 11:28:04 · 2 answers · asked by bigpapamarek 1 in Science & Mathematics ➔ Physics

2 answers

F = qvB sin (angle)

That should be what you need to know. Force is a vector cross product of velocity and magnetic field. Solve for the angle and you should get the correct answer.

2007-03-25 11:34:40 · answer #1 · answered by msi_cord 7 · 0⤊ 0⤋

80.7 degrees

2007-03-25 11:41:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋