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Calculate the percentage of [ CaCO3 ] in Chalk if it's found that 2gm of [CaCO3] require 300ml of 0.1N HCL for complete solubility and neutralization..

2007-03-25 10:20:37 · 2 answers · asked by M T 1 in Science & Mathematics Chemistry

2 answers

Check out this site
http://www.ausetute.com.au/titrcalc.html

2007-03-25 10:39:05 · answer #1 · answered by Anonymous · 0 0

You've got 0.03 mol of HCl, which corresponds to 0.015 mol of CaCO3.

0.015 mol of CaCO3 weighs 0.015 x 100 = 1.5g.

Now all you have to do is to work out what percentage 1.5g is of 2g!

2007-03-25 10:36:18 · answer #2 · answered by Gervald F 7 · 0 0

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