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The intensity of solar radiation at the top of Earth's atmosphere is 1340 W/m3. Assuming that 60% of the incoming solar energy reaches Earth's surface and assuming that you absorb 50% of the incident energy, make an order-of-magnitude estimate of the amount of solar energy you absorb in a 60 minute sunbath. (Assume that you occupy a 1.7 m by 0.3 m area of beach blanket and that the sun's angle of elevation is 60°.)
change in E = 10^___J

2007-03-25 10:16:05 · 1 answers · asked by Thumper 1 in Science & Mathematics Physics

1 answers

Hi. 1340 W/m^2 is what you mean, I think. 1340 times .6 times .5 times (1.7 times .3). You can convert to Joules.

2007-03-25 10:23:04 · answer #1 · answered by Cirric 7 · 0 0

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