can anyone solve and explain the steps for:
the molar heat of fusion for water is 6.009 kJ/mol. How much energy would be required to melt 12.75 mol of ice?
2007-03-25 09:25:35 · 3 answers · asked by beentherestillthere 2 in Science & Mathematics ➔ Chemistry
It is a straight multiplication
You have 12.75 mols X 6.009 KJ /mol.
2007-03-25 09:32:51 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋
If risk is given, anticipate you have one hundred g of the compound, changing each and every % image with "g". often cases, g gadgets are already given. one million. Convert each and every mass into moles. (76.5 g C)(one million mol/ 12.0 g) = 6.375 moles C (12.one million g H)(one million mol/one million.0 g) = 12.0 moles H (eleven.3 g O)(one million mol/sixteen.0 g) = 0.706 moles O 2. Divide each and every mole quantity by utilising the smallest quantity and get 9.03 mol C 17.0 mol H one million.00 mol O This ultimately finally leads to an empirical formula of C9H17O, which could have a molar mass of 141. To get the molar mass given in the priority, you will would desire to need to double the empirical formula: C18H34O2, which will grant you a molar mass of 242. So C18H34O2 is the molecular formula.
2016-11-23 15:04:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Just multiply those two numbers together!
2007-03-25 09:32:18 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋