I need to know a possible way to do this for a physics project. The lightbulb must be in working condition, and it must be on an active circut that has a current running through it. The lightbulb cannot be broken, and I can't just use a huge resistor, because there would still mathematicly be a small current going through the bulb. Any ideas?
2007-03-25 09:02:24 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Apply + voltage to both sides of the circuit. If both sides of the bulb are at the same potential, it won't light up.
2007-03-25 09:19:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
A lightbulb only glows when there's enough electricity going through it, but the wiring's still hooked up to work. I think if you put a tiny amount of electricity through, it won't glow. You could use a dimmer switch to control the electricity...
2007-03-25 09:08:10 · answer #2 · answered by Moral Orel 6 · 1⤊ 0⤋
you could put a switch on that circuit
if the switch was off, then it wouldn't light
or a blown fuse
2007-03-25 09:06:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋
dont ground the circuit
2007-03-25 09:05:05 · answer #4 · answered by Anonymous · 1⤊ 0⤋
this doesn't sound possible
2007-03-25 09:06:48 · answer #5 · answered by MrKnowItAll 3 · 0⤊ 0⤋