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f(x)= e^x^2
and f'(x)= 2xe^x^2 is is alright coz the formula is e^u * u' right?

2007-03-25 07:31:31 · 3 answers · asked by mistikaaaaa 1 in Science & Mathematics Other - Science

3 answers

[ e^f(x) ] ' = [e^(f(x))] * f'(x)

i think you are right

2007-03-25 07:35:47 · answer #1 · answered by gjmb1960 7 · 0 0

Yes. The derivitive of e^u = (du/dx) e^u.

Therefore since the derivitive of x (squared) is 2x then the derivitive of e^x (squared) will equal:

2x e^x (squared)

2007-03-25 14:42:25 · answer #2 · answered by What?!! 1 · 0 0

Try the NEGATIVE EXPONENT First!

Thanks, RR

2007-03-25 14:34:05 · answer #3 · answered by Anonymous · 0 0

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