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Assumptions: A mass is sliding down a 3000 m ramp which drops 800 m with a frictional force opposing the motion of 210 N. This is a guess based on my telepathic powers; all required info that you failed to state.

A force diagram will show the gravitational force accelerating the mass to be 90g*(800/3000). The net acceleration force is that # minus 210 N.
a = Fn/m = (235.2-210)/90 = .28 m/s²
v² = 2ad and KE = ½mV²→ KE = mad = 90*.28*3000 = 75600 J

2007-03-25 07:15:48 · answer #1 · answered by Steve 7 · 1 0

KE = 1/2 mv^2 = mgh - Fd = PE - work against friction. Fd = 210 N X 3000 m

Thus KE = mgh - Fd = 90 X 9.81 X 800 - 210 X 3000 you can do the math. The answer is in Newton-meters (aka Joules).

Lesson learned: Without friction all the potential energy (mgh) would convert to KE. But with friction the work (Fd) must be subtracted out because that energy is lost to heat rather than changing to KE.

2007-03-25 07:34:48 · answer #2 · answered by oldprof 7 · 0 0

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2016-12-15 08:28:55 · answer #3 · answered by scheiber 4 · 0 0

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