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Find the equation of the line containing (6, -2) and (6, 3).

2007-03-25 05:44:38 · 5 answers · asked by Landy J 1 in Education & Reference Homework Help

5 answers

find slope first
m = (y2 - y1) / (x2 - x1)

m = (3 - (-2)) / (6 - 6)

m = 5/0. Since you can't divide by 0, the slope is undefined.

the equation is x = 6

2007-03-25 05:48:05 · answer #1 · answered by      7 · 0 1

First slope formula:
y1-y2/x1-x2

(6-3)/(-2-3) = 3/-5 = -3/5

plug this into the equation of a line = y = mx + b, where m is slope and b is y-intercept. You can use either of the points for this

3 = (-3/5)(6) + b

3 = -18/5 + b

15/5 = -18/5 + b

33/5 = b


so, y = -3/5x + 33/5

2007-03-25 12:48:48 · answer #2 · answered by crzywriter 5 · 0 2

x=6?

the slope is undefiined so a conventional y=mx+b formula is not possible!
3- -2 / 6-6 = 5/0 Undefined!

2007-03-25 12:52:58 · answer #3 · answered by JimBob 6 · 0 0

just take the slope of the points. that's "m" in the y=mx+b. to find b which is the y intercept, substitute one of the coordinates in for x and y and solve for b

2007-03-25 12:48:55 · answer #4 · answered by stitchfan85 6 · 0 0

you can just draw the graph.Very easily you can find the answer as x=6

2007-03-25 12:58:54 · answer #5 · answered by pranay 1 · 0 0

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