A 0.094 kg meter stick is supported at its 40 cm mark by a string attached to the ceiling. A 0.62 kg object hangs vertically from the 6.77 cm mark. A second mass is attached at another mark to keep it horizontal and in rotational and translational equillibrium. The acceleration of gravity is 9.8 m/s^2. If the tension in the string attached to the ceiling is 20.1 N, find the value of the second mass.
2007-03-25 05:04:00 · 2 answers · asked by krstilyzed 1 in Science & Mathematics ➔ Physics
The tension is supporting the total mass of the 3 objects.
T = mtotal*g = m1*g + m2*g + m3*g
Calculate the mass of the 3rd piece, m3.
There's no need to do any calculations to balance the torques. I started to before re-reading the question.
2007-03-25 09:17:39 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
i don't know chek one more time
2007-03-25 12:08:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋