I'm confused by this question, because it seems that I should find the kinetic energy but I'm looking for work... please help
2007-03-25 03:11:17 · 4 answers · asked by Hannah 1 in Science & Mathematics ➔ Physics
The work done is equal to the kinetic energy of the bullet.
Kinetic energy=1/2 x mass x speed^2
=6000 joules
2007-03-25 03:17:22 · answer #1 · answered by Mystique 1 · 0⤊ 1⤋
Work is force multiplied by distance. So, with the given data, it is not possible to answer. If the bullet hits an object with that velocity and penetrates some distance x, it can be computed.
2007-03-25 03:59:24 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
If it's one of those questions where it's a vacuum, none. After initial acceleration, the bullet is in freefall and not doing any work. If it's in air, the aerodynamics of the bullet would decide.
2007-03-25 09:16:00 · answer #3 · answered by Nomadd 7 · 0⤊ 0⤋
Work done by bullet=K.E. lost=1/2 m v^2
then just subst. in the given values at SI unit
2007-03-25 03:16:14 · answer #4 · answered by llcold 2 · 0⤊ 0⤋