problem: a drilling machine operates with an electric power consumption of 840 W. How much does it cost to operate the machine continuously for 8 hours if the elctricity costs $0.080/kwh?
thanx. i need ur help.
2007-03-25 02:48:32 · 4 answers · asked by mulan 1 in Science & Mathematics ➔ Physics
Energy (E) is power (P) times time (t)
E=P t
Cost = E (rate)
Cost = P t rate
Cost=840 x 8 hours (0.080/kwh) (1/1000)
Cost=$.537
2007-03-25 02:50:49 · answer #1 · answered by Edward 7 · 2⤊ 0⤋
You just multiply the power consumed in kilowatts (.84kw) times the hours it's consumed (8), and that times the cost in dollars per kwh($.08)
2007-03-25 09:18:28 · answer #2 · answered by Nomadd 7 · 0⤊ 0⤋
What's the tax rate? Does the electricity cost include delivery cost charged by the grid operator? :)
2007-03-25 03:40:32 · answer #3 · answered by Yau 2 · 0⤊ 0⤋
This is fairly straight forward. Find the total energy used : multiply the power X how long is was used.
Since you are paying by the kilowatt hour and kilowatts are thousands., divide by 1000 and then multiply by the cost of a kilowatt hour.
2007-03-25 02:53:34 · answer #4 · answered by Gene 7 · 0⤊ 1⤋