The mean hight of 15 students in 1st period class is 64 inchs, and the mean hight of 28 students in 8th period class is 69 inchs. Find the mean hight of all students in both classes and round to the nearest hundredth of an inch.
2007-03-25 01:40:51 · 7 answers · asked by ? 1 in Science & Mathematics ➔ Mathematics
let
64 x 28 = 960
69 x 28 = 1932
1932 + 960 = 2892
Total students = 15 + 28 = 43
Divide 2892 by 43
2892 / 43 = 67.25581395 is the mean
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2007-03-25 02:43:36 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Mean height of 15 students in 1st period class is 64 inches
Therefore their combined height = 15*64 = 960 inches
Mean height of 28 students in 8th period is 69 inches
Therefore their combined height = 28*69 = 1932 inches
Mean height of all the students
= (Total height)/(Total number of students)
=(960+1932)/(15+28)
=67.26 inches (rounded off to nearest hundredth)
2007-03-25 08:47:47 · answer #2 · answered by Ashley 2 · 0⤊ 0⤋
The total height of all students in 1st period class is:
15*64 " = 960 "
The total height of all students in 8th period class is:
28*69 " = 1932 "
Total for both classes: (960 + 1932) " = 2892 "
Total number of students: 15 + 28 = 43
Mean height = 2892/43 " = 67.2558... "
â´ mean height = 67.26 inches (to the nearest one hundredth)
2007-03-25 08:47:09 · answer #3 · answered by sumzrfun 3 · 0⤊ 0⤋
the sum of hights of the students in 1st class has to be: 64*15=960
the sum of hights of the students in 1st class has to be:
69*28=1932
so their heigh in total is 960+1932=2892
now you have 15+28=43 students
mean height=2892/43=67.26
2007-03-25 08:50:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(15*64 + 28*69)/43 = 67.26 inches
2007-03-25 08:46:56 · answer #5 · answered by blighmaster 3 · 4⤊ 0⤋
I'll give you a hint,, "mean" is the average
like if you had one student 5 ft tall and one 4 ft tall, the mean is 4.5ft,,
2007-03-25 08:47:11 · answer #6 · answered by Jo Blo 6 · 0⤊ 0⤋
67 inches.
2007-03-25 08:49:12 · answer #7 · answered by Anonymous · 0⤊ 0⤋