Give me some example of computation?
2007-03-22 01:40:35 · 4 answers · asked by Shadow 2 in Science & Mathematics ➔ Engineering
*Character D for Deformed steel and next numbers stand for nominal diameter.
*Ex.: D10: Deformed steel bar and its nominal diameter is 10mm. (0.01m)=
*Specification JIS G3112 - SD295A .
*Standard length :11.7 m
*volume of a D10 round bar
=pi*radius^2*length
=3.14*[0.01/2]^2*11.7[radius=diameter/2]
=0.00092 m^3
Now,total weight
=0.00092 *7850
=7.21 kg.
*the weight of D10 steel bar per meter
=total weight/total length
=7.21/11.7
=0.62 kg/meter.
=620 gram/meter.
2007-03-22 03:04:54 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Steel Bar Weight Per Meter
2016-12-18 06:32:22 · answer #2 · answered by gnegy 4 · 0⤊ 0⤋
Hi! Treat it as a cylinder and multiply the outcome of the volume (pi x radius squared x length) by the known weight of the steel ( usually around 8000kg per cubic metre)
e.g bar = 10cm wide and 1500cm long
radius = 5cm
pi (3.142) x 5 squared (25) x l500 (length) = 117825cc
1cc = 0.008kg (8grammes)
117825 x 0.008kg = 942.6kg
2007-03-22 02:20:10 · answer #3 · answered by ray trigg 1 · 0⤊ 0⤋
you can see it as per astm standards,the sp gravity of steel..then solve it from there, you shuold know it.
2007-03-22 02:19:14 · answer #4 · answered by juandahon 1 · 0⤊ 0⤋