Find the derivative 5/x+x?

Answer 1

let's get into the first term first:
5/x
when getting the derivative of this form, that is a fraction of variables, I am using a memory aid formula, that is:
lo de hi hi de lo over lo lo
lo means number below the over, hi means the number at the top of the over and de means derivative. so this memory aid means denominator times the derivative of the numerator minus the numerator times the derivative of the denominator all over the denominator squared.

so, d(5/x +x) = [x(0) - 5(1)]/x^2] + 1
this gives: -5/x^2 + 1

Answer 2

-5/x^2 + 1

Answer 3

(-5/x^2) +1

Answer 4

So you would have to setup the equation

d/dx (5/x+x)

by the addition property, you can treat this as
5*d/dx (1/x) + d/dx(x) (and put the 5 in front since its constant)

then it would be simple to solve using the basic power rule
which would be
d/dx(x^n) = nx^(n-1)

which would be

-5x^-2 + 1 (using the identity that 1/x = x^-1)

Answer 5

d(5/x) = 5 *d( x^-1) = 5*(-1x^-2) = -5x^-2 = -5/x²

d(x)= 1

so d(5/x +x) = -5/x² +1

Answer 6

dy/dx = 5/x**2 -1

Answer 7

y=(5/x)+x
y'=(-5/x^2)+1

Answer 8

-5x^(-2) + 1?

sorry someone posted-i didn't see that post o.O

Answer 9

5(2x)

Answer 10

now?