What connection should use by using npn transistor to amplify output current from μcontroller to actuate motor

Question

what configuration I should use to amplify my output current?what type of npn transistor hv low input current and can generate high output current?how should I connect them?

sorry....forget to mention...
my motor is DC motor....the output is from microcontroller....

now I am using C9013....do you hv good suggestion of transistor which can provide higher output current...
my desired output current is 50mA..

we r using relay to switch motor...
but the output from PIC is low...so sometimes it can work but sometime cant....therefore we trying to get higher current for it...

do u think we should direct connect the current to on the motor or need the help from relay?

Does power transistor require high input current or voltage?

y need heat sink for motor?
I didnt plan to get rid of the heat,is it v important?y?

Answer 1

Need more info---

What kind of motor? Stepper? DC? AC (waveform created by controller)? AC (power from utility)?

You usually need power transistors that require a heat sink for motors. What type of NPN do you have? How much "high current" do you need? How are you planning to get rid of the heat?


UPDATE:
Relays are easier to work with --

You can use the transistor to turn the relay on, which then closes its contacts and turns on the motor. The relay coil should be connected (with the proper polarity) to the collector and then to a power supply that it can work with +12V? +5V? +15V? You should put a diode across the relay coil (if it doesn't already have one), cathode to the power supply, to eliminate any back EMF from the relay destroying your transistor. The emitter should connect to ground, and the base should go through a resistor (1k? 2k?) to the controller output bit.

Most relay coils don't take very much current, compared to what a transistor can handle, but it's usually more than the output of a microcontroller. I don't recognize the transistor (the number actually looks like a date code), but if it can handle the small (100mA?) current of the relay coil, it should be OK without a heat sink (the motor doesn't need a heat sink, but some transistors do).

Good Luck!

Answer 2

It extremely relies upon on the circuit and the form of transistor. it ought to be the two or the two. It makes use of the skill from the DC bias grant that's mandatory for that's operation. working example, a junction transistor in trouble-loose emitter configuration will boost the two. A FET will, because of the fact of that's totally severe enter impedance, boost modern-day by utilising a super volume and likewise voltage. An emitter follower or a source follower would not boost voltage yet does boost modern-day.

Answer 3

sophisticated factor. browse on google or bing. this could help!