2007-03-21 01:40:07 · 3 answers · asked by ronzrex 1 in Science & Mathematics ➔ Engineering
You'll have to buy a new meter after it blows up!
2007-03-21 02:58:36 · answer #1 · answered by NJGuy 5 · 0⤊ 0⤋
The meter uses ohms law to measure current and voltage. If you want to find a resistance, the meter applies a known regulated voltage across the leads, and measures current, does the math, and ouputs the reading in resistance.
If you apply an unknown(unknown to meter) voltage to the resistor that you are measuring, then it throws the computation off and you will get a false reading.
2007-03-21 09:27:48 · answer #2 · answered by joshnya68 4 · 0⤊ 0⤋
REMEMBER RESISTANCE AND CAPACITANCE SHOULD BE CHECKED WITHOUT POTENTIAL DIFFERENCE PRESENT IN THE CIRCUIT.
IF THE VOLTAGE WERE TO BE APPLIED IN THE CIRCUIT THEN YOU WILL NEVER BE ABLE TO GET AN ACCURATE READING ,THE READINGS WILL KEEP FLUCTUATING ,HENCEFORTH WE NEED TO DISCONNECT VOLTAGE SUPPLY IN A CIRCUIT BEFORE TAKING READINGS OF THEIR VALUE.
2007-03-21 10:37:11 · answer #3 · answered by kirk b 3 · 0⤊ 0⤋