2007-03-19 04:08:13 · 3 answers · asked by gabster 1 in Science & Mathematics ➔ Engineering
VOLTAGE DROP: The voltage developed across a component or conductor by the flow of current through the resistance or impedance of that component or conductor.
(DROP) = (CURRENT) * ( IMPEDANCE)
Remember, inductive impedance is positive; capacitive impedance is negative. "PF" stands for load power factor.
The approximate formula is:
(Drop) = current * (resistance * cos(PF) + reactance * sin(PF))
2007-03-19 08:49:10 · answer #1 · answered by CanTexan 6 · 0⤊ 0⤋
Without knowing the specifics of your circuit, it is hard to give a specific answer but, here are some general equations. The basic equations are V=iR and P=Vi. V=voltage, i=current in amps, P= power in Watts. Solve for what you need. Apply this to a circuit using node or mesh methods. For a 2 resistor series / parallel circuit (your load is often the parallel resistance), you can do an easy voltage divider.
2007-03-19 04:45:42 · answer #2 · answered by photoman 1 · 0⤊ 0⤋
Voltage = Current x Resistance
2007-03-19 07:32:19 · answer #3 · answered by joshnya68 4 · 0⤊ 0⤋