how do i find the numbers (that are real) which satisfy these equations:
a) [2x -1] = 3
b) [x + 2] = 2[x] -3
c) [x] = [2x]
2007-03-17 23:13:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Do you mean "absolute value" instead of the brackets?
|x| instead of [x]
If it's absolute value:
a)
|2x - 1| = 3
means
2x -1 = 3 AND 2x - 1 = -3
2x = 4 AND 2x = -2
x = 2 AND x = -1
2007-03-17 23:22:02 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
a) [2x -1] = 3 ==> 2x = 3 + 1 ==> 2x = 4 ==> x = 2
b) [x + 2] = 2[x] -3 ==> x -2x = -3 - 2 ==> ==> -x = -5 ==> x = 5
c) [x] = [2x] ==> x = 0
2007-03-18 06:24:53 · answer #2 · answered by physicist 4 · 0⤊ 0⤋
a) 2x - 1 = 3
2x = 4
x = 2
b) x + 2 = 2x -3
x = 5
c) x = 2x
2x - x =0
x = 0
2007-03-18 06:25:25 · answer #3 · answered by maplesyrup 1 · 0⤊ 0⤋
Do you mean "absolute value" instead of the brackets?
|x| instead of [x]
If it's absolute value:
a)
|2x - 1| = 3
means
2x -1 = 3 AND 2x - 1 = -3
2x = 4 AND 2x = -2
x = 2 AND x = -1
2007-03-18 07:01:22 · answer #4 · answered by cute 1 · 0⤊ 1⤋
By using brackets, are you referring to the
greatest integer function(or floor function)?
Your question isn't clear to me. Sorry!
2007-03-18 10:15:15 · answer #5 · answered by steiner1745 7 · 0⤊ 0⤋