How do you factorize a cubic equation.???

Question

I dont want to use hit and trial method.

Answer 1

Unfortunately, the "hit and trial" method is the only way to factorize cubics which cannot be factored by grouping. The cubic formula is way too complex to bother to use.

There are, however, ways to reduce the number of factors you need to check (such as Descartes' rule of signs). But other than that, I can only suggest that you know how the hit and trial methods work (i.e. testing factors of d/a, where
ax^3 + bx^2 + cx + d = 0) and then realizing that if r is a root,
(x - r) is a factor, and to use long division of (x - r) into
ax^3 + bx^2 + cx + d to obtain a quadratic.

Answer 2

eg. y^2+3y+2

find waht goes in to 1 and 2
( and can mulltiply to give 2 for +2 and can sum up to give 3 (3Y)) these numbers are 1 and 2.
do this , (y )(y )
and put (y+1)(y+2) 1 &2 in.

it can get more complicated but lets stay on the safe side