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x – 13 / x^2 – x – 12

+

3 x – 3 / x^2 – x – 12

2007-03-17 19:18:54 · 3 answers · asked by archie g 1 in Science & Mathematics Mathematics

3 answers

x^2 -x -12 = (x-4)(x+3)

(x-13)/(x^2 -x -12) + (3x - 3)/(x^2 -x -12) = 4(x-4)/(x^2 -x -12)
=4(x-4)/(x-4)(x+3) = 4/(x+3)

2007-03-17 19:28:52 · answer #1 · answered by astrokid 4 · 0 1

(x - 13/ x^2 - x - 12) + (3x - 3/ x^2 - x - 12)
= {(x - 13) + (3x - 3)}/ x^2 - x -12)
= x - 13 + 3x - 3/ x^2 - x -12
= 4x- 16/ x^2 - x - 12
= 4(x - 4)/ (x + 3)(x - 4)
= 4/ (x +3)

2007-03-18 02:29:48 · answer #2 · answered by Anonymous · 0 1

(x-13/x²-x-12) +(3x-3/x²-x-12)

(x-13 +3x-3)/(x²-x-12)

(4x-16)/(x²-x-12)

4(x-4)/(x-4)(x+3)

4/(x+3)

2007-03-18 02:38:13 · answer #3 · answered by Winnie 3 · 0 1

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