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the concorde is 62 m long when its temperature is 23 degrees C. in flight, the outer skin of this supersonic aircraft can reach 105 degrees C due to air friction. the coefficient of linear expansion of the skin is 2.0 X 10^-5 (C-degrees)^-1. find the amount by which the concorde expands?

2007-03-17 19:18:39 · 3 answers · asked by tico 1 in Science & Mathematics Physics

3 answers

62*2x10^-5*82 m = 10.168 mm

2007-03-17 19:38:14 · answer #1 · answered by ag_iitkgp 7 · 0 0

∆L = 62(2.0 X 10^-5)(105 - 23)
∆L = 10.168 cm

2007-03-18 02:37:28 · answer #2 · answered by Helmut 7 · 0 0

expansion in length= L*a* dt where dt = rise in temp, a = coeff of expansion, L = initial length

2007-03-18 02:22:06 · answer #3 · answered by astrokid 4 · 0 0

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