I got 8x² is that right?
2007-03-17 18:27:19 · 10 answers · asked by topcook15 1 in Science & Mathematics ➔ Mathematics
No.
Remember, (x+4)^2 is actually
(x+4)(x+4)
Using FOIL (First, Outside, Inside, Last) method of multiplication, you get:
x^2+8x+16
Hope this helps!
2007-03-17 18:30:55 · answer #1 · answered by p37ry 5 · 0⤊ 0⤋
X^2+8X+16
2007-03-18 01:31:19 · answer #2 · answered by 1040 Agent 2 · 0⤊ 0⤋
x^2 + 8x + 16
2007-03-18 01:32:22 · answer #3 · answered by 7 · 0⤊ 0⤋
(x+4)² = (x)²+(4)²+2(x)(4) = x²+16+8x
2007-03-18 01:36:26 · answer #4 · answered by Umer 2 · 0⤊ 0⤋
No it is not ,you simply but it this way
(x+4)^2 = (x+4)*(x+4) =x^2 + 4x + 4x + 16
which ended like
x^2 + 8x +16
Or use the general equation
(a + b)^2 = (a^2) +(2 *a*b) + (b^2)
2007-03-18 02:02:25 · answer #5 · answered by ? 3 · 0⤊ 0⤋
by applying the formula (a+b)^2=a^2+2ab+b^2 ,we get x^2+8x+16 so 8x^2 is not right
2007-03-18 03:36:06 · answer #6 · answered by Twarita 2 · 0⤊ 0⤋
no
the general form of (a+b)^2=a^2+2ab+b^2
here a=x and b=4
now substitute
(x+4)^2=x^2+2(4)(x)+(4)^2
that is equal to
x^2+8x+16
2007-03-18 01:32:28 · answer #7 · answered by satwik 2 · 0⤊ 0⤋
(x+4)(x+4)=x^2+4x+4x+16=x^2+8x+16
2007-03-18 01:30:28 · answer #8 · answered by live4hoping 2 · 0⤊ 0⤋
You better not be cheating. First of all, use distributive property:
(x+4)^ 2 = x^2 + 4^2.
Last, simplify.
x^2 + 16.
Your first answer was incorrect: 4 x 4 is equal to 16, not 8. Oh yes, and you better not be cheating, now that I've taught you simple baby math.
2007-03-18 01:34:58 · answer #9 · answered by Eric Ho 2 · 0⤊ 1⤋
NO.
This is the rule:
(a+b)^2= a^2+2ab+b^2
It's always, the first term square... first x second x 2... second term square...(Using their respective positive or negative signs)
2007-03-18 01:38:42 · answer #10 · answered by john.bt 2 · 0⤊ 0⤋