I got r² + 5 is that right?
2007-03-17 18:19:06 · 9 answers · asked by gizzie76 1 in Science & Mathematics ➔ Mathematics
your close... but not correct:
Heres your solution:
(r-5)(r+1)
= (rxr) + (r x1) + (-5xr) + (-5 x 1)
= r^2 + r - 5r - 5
= r^2 -4r -5
there ya go!
2007-03-17 18:25:55 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The answer above is correct.
first you multiply the r in (r-5) by r and by +1, leaving you with r^2 + 1r.
The you would multiply the -5 by r and by +1, leaving you with -5r -5.
So in total you have r^2+1r-5r-5.
When you combine the like terms (+1r-5r) you end up with:
r^2-4r-5
2007-03-18 01:27:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Use the FOIL technique. (First, Outside, Inside, Last) to solve this problem.
First: r * r = r^2
Outside: r * 1 = r
Inside: -5 * r = -5r
Last: -5 * 1 = -5
r^2 + r - 5r - 5
r^2 - 4r - 5
2007-03-18 01:38:50 · answer #3 · answered by Stuckart 3 · 0⤊ 0⤋
It's r^2 -4r-5. If you are having trouble with this kind of problem, see your teacher, or a smart friend.
2007-03-18 01:27:55 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
the simplification is r^2+r-5r-5
on sipmlification, the answer is
r^2-4r-5
2007-03-18 02:30:03 · answer #5 · answered by Yoga 2 · 0⤊ 0⤋
it's r2 - 4r - 5
you have to:
r*r + r*1 - 5*r -5*1
2007-03-18 01:24:00 · answer #6 · answered by Claudita 1 · 0⤊ 0⤋
r^2-4r-5 do foil, best tool for algebra
2007-03-18 01:25:36 · answer #7 · answered by bretwm1990 1 · 0⤊ 0⤋
r^2 - 4r - 5
you need to foil it out
2007-03-18 01:22:44 · answer #8 · answered by Class PandorTRT 2 · 0⤊ 0⤋
It is very easy, you can do it
2007-03-18 02:31:12 · answer #9 · answered by JAMES 4 · 0⤊ 0⤋