Math Help Please Text isnt teaching me anything?

Question

Solve x / 5x + 10 + x - 3 / x + 2 = 7 / 5

Answer 1

x / 5x + 10 + x - 3 / x + 2 = 7 / 5

Well, the x in the first fraction cancel...

1/5 + 10 + x - 3 / x + 2 = 7 / 5

Combine like terms...

12 1/5 + x - 3 / x = 7 / 5

Multiply everything by x to get it out from the denominator

12 1/5 x + x² - 3 = 7/5 x

Since we have a quadratic equation (x²), set it equal to zero and solve

x² + 10 4/5 x - 3 = 0

Quadratic Formula

x = (-27 +/- 2 *sqrt(201))/5

Answer 2

I dont know if this helps but you want to get the x's on one side of the equal sign and the rest on the other.

(x/5x)+10+x-(3/x)+2=7/5
*First cross out x's in (x/5x)
1/5+10+x-(3/x)+2=7/5
*Second get x's on one side and find common denominator
1/5+10(5/5)+2(5/5)-(7/5)=(3/x)-x(x/x)
(1/5)+(50/5)+(10/5)-(7/5)=(3/x)-((x^2)/x)
(54/5)=(3-(x^2))/x
*multiply both sides by x because you want to get it in a ax^2 +bx+c = 0 form so you can use the quadractic formula.
-x^2 - (54/5)x +3 = 0
* use quadratic formula to find x
x= (-b+ or - (the square root of (b^2 - 4ac)))/2a

So I got x= approx -11.07 or x= 0.27. I don't what grade you are in or age, but a graphing calculator works great to double check. I'm sure that's it. I'm in college and went up to calc 2 and haven't touch this for awhile. good luck!

Answer 3

x/(5x+10)+(x+3)/(x+2)=7/5
5x+10 not=0 5(x+2) not=0 and x+2 not=0
so x not=-2
x/5(x+2)+(x+3)/(x+2)=7/5
same nominator
x+5(x+3)=7*(x+2)
x+5x+15=7x+14
x=-1 solution

Answer 4

Start by multiplying the whole thing by 5x, giving:
x + 50 x + 5x^2 - 15 + 10x = 7x. Collect terms:
5 x^2 +54x -15 = 0. Apply quadratic formula:
x = (-54 +/- sqrt(2916 + 300))/10 or
x = (-54 +/- 56.71)/10 or
x = 0.271 or -11.071
Finally, verify that 5x is not zero, and x is not zero, so that the original division is defined. This checks, so we're done.

Answer 5

be more specific, you are missing parentheses.