Hard alegbra question. need some help?

Question

North Avenue is 88 feet wide when it ends at Main Street. A 137 foot long diagonal crosswalk allows pedestrians to cross Main Street to or from either corner of North Avenue. Determine the width of Main street.

Main Street is _____________ft wide.

Answer 1

105 feet, by the Pythagorean theorem.

Answer 2

Draw this out and you will see that North Ave is the base of a right triangle, 88 feet wide; the diagonal is the hypotenuse and is 137 feet long.
Let w be the width of Main street
then w^2 + 88^2 = 137^2
w^2 = 137^2 - 88^2 = 18769 - 7744 = 11025
Take the square root of both sides:
w = 105 feet long

Answer 3

Let width of North Street be x

x^2 + 88^2 = 137^2
Therefore x = sqrt (137^2 - 88 ^2)
= sqrt (18769 - 7744)
= sqrt (11025)
= 105

Main street is 105 ft wide

Answer 4

it forms a right triangle with one side equal to 88 ft. and the hypotenuse equal to 137 ft. You need to solve for the last side.

Use Pythagorean's Theorem: a^2 + b^2 = c^2

a = 88
c = 137
solve for b

88^2 + b^2 = 137^2
137^2 - 88^2 = b^2
square root both sides and you get b = 105

Answer 5

a^2 + b^2 = c^2 where a=88 and c=137. You should be able to get it from there.

Answer 6

105ft

It's a simpe triangle rectangle. The problem can be represented as this:
http://upload.wikimedia.org/wikipedia/commons/8/8d/Triangle_rectangle.png

You have the value of the hypothenuse (h) and of one side (Cb) and you want to find Ca. By Pythagorean's theorem you have:

h^2 = a^2 + b^2
h^2 - b^2 = a^2
a^2 = (137)^2 - (88)^2
a^2 = 11025
a = sqr(11025)
a = 105ft