The temperature of a brass cylinder of mass 100g was raised to 100 degree celsius and then transferred to a thin aluminium can of negligible heat capacity. The aluminium can contained 150g of paraffin at 11 degree celcius. If the final steady temperature after stirring was 20 degree celsius, claculate the specific heat capacity of paraffin
(Neglect heat losses, and assume specific heat capacity of brass= 38 J/gK
2007-03-17 16:17:12 · 2 answers · asked by Chocolate Strawberries. 4 in Science & Mathematics ➔ Physics
JAMES: Why didn't you take the weight of the cylinder into account
2007-03-17 17:05:00 · update #1
The brass went from 100deg down to 20, a difference of 80 deg. 80 deg difference means that 38*100g*80= 304,000Joules were transfered to the parafin.
304,000J raised 150g from 11 to 20 deg, a difference of 9 deg.
304,000/(9*150)= 225 for the heat capacity of parafin.
2007-03-17 16:27:12 · answer #1 · answered by xaviar_onasis 5 · 1⤊ 0⤋
100*(100-20)*38/150*(20-11)
=100*80*38/150*9
=225
2007-03-17 16:58:45 · answer #2 · answered by JAMES 4 · 0⤊ 0⤋