A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular?

Question

A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 4.00 rev/s while rotating through three-fourths of a revolution. How much time does this maneuver take?

Answer 1

need more information like her radius

edit nm

vf^2-vi^2=2ad

angular acceleration = 4.66666 rev/s^2

d = 1/2 a t^2

.75 = 1/2 (4.666) t^2
t= .567s

Answer 2

She needs to first break the 10m/s-1 mark to beat the gravitational pull and get air born first.

As for the question it should only take a fraction of a second.