Find an equation of the tangent line to the curve y= -sin x-5sin^2 x at the point (0, 0).
2007-03-17 15:56:29 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
find the slope at that point (derivitive)
y=mx+b
since it intersects the y axis at (0,0), b=0
so
y=mx
2007-03-17 16:00:43 · answer #1 · answered by Fudge 2 · 0⤊ 0⤋
take derivative of the curve at point (0,0) to find the slope. which is also the slope of the tangent line. The line has a form of y = ax +b with a is the slope and b is a point it pass through. You already know the slope a. Since the line goes through (0,0) which is origin, there is no b, b=0. In general if the point is not the origin, substitute the point into the line equation to find b. Then you got the tangent line. Good luck
2007-03-17 23:10:10 · answer #2 · answered by tuoidabuon 2 · 0⤊ 0⤋
You have to find the slope which is the derivative at (0,0)
y'= -cos x-10sinx*cosx which at x= 0 = -1
so the tangent is y=-x
2007-03-17 23:03:10 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋