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2007-03-17 14:54:34 · 36 answers · asked by keisha2305 1 in Education & Reference Trivia

Maybe you need brains. have you ever heard of lateral thinking, systematic has.

dumbos

2007-03-17 15:33:26 · update #1

36 answers

As often as I can talk him into it!!

2007-03-17 15:06:21 · answer #1 · answered by libbyft 5 · 0 1

2 goes 34 times in 69

2007-03-18 09:32:27 · answer #2 · answered by Anonymous · 0 0

2 x 3 = 6
2 x 4 = 8
9 - 8 = 1
So, 34 remainder 1

2007-03-17 15:00:46 · answer #3 · answered by timeworld 2 · 0 0

there are 8 2's that goes in 69, if it was a trick question, it's 2,12,22,32,42,52,62, if it was a serious one the answer would be 34 remainder 1

2007-03-17 23:28:09 · answer #4 · answered by warp 1 · 0 0

34 with 1 left over

2007-03-17 15:05:39 · answer #5 · answered by Anonymous · 0 0

30 remainder of 1

2007-03-17 17:25:29 · answer #6 · answered by LoveStruckBoy18 2 · 0 0

34 carry over 1

2007-03-17 15:18:10 · answer #7 · answered by Anonymous · 0 0

69....

If you have a box that holds 2 somethings and you have 69 of these boxes.

2007-03-17 18:27:16 · answer #8 · answered by nonono 3 · 0 1

34, with a remainder of 1

Did you catch that everyone? The Asker just called us dumbos! But at least our stupidity is exceeded by her own for posting this question in Trivia instead of Words & Wordplay when she wasn't looking for a serious answer.

2007-03-17 14:57:06 · answer #9 · answered by greymatter 6 · 0 0

It goes in once........after you take the first lot of 2 away, you are seeing how many times does 2 go into 67, then 65, 63, 61, 59, 57, 55 etc.....

2007-03-17 14:59:44 · answer #10 · answered by squeegy 4 · 0 1

I had an answer to this question all typed out - slowly and with difficulty because I find keyboards awkward - and got shoved into "registering", which, of course, lost my answer. I am, therefore, apologetic that you have been denied the best answer to your question, but really cross that the system has been the cause of that denial.

2007-03-17 15:17:43 · answer #11 · answered by Anonymous · 0 0

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