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How long will the astronaut need to fire a 100.0 N rocket backpack to stop the motion relative to the spacecraft?

2007-03-17 10:33:50 · 5 answers · asked by Hannah 1 in Science & Mathematics Physics

5 answers

Force = Mass * Acceleration

F=ma

100.0 N = 200.0kg * a

a = 0.5 m/s^2

Velocity Final = Velocity initial + acceleration * time

Vf = Vi + at

Since we are decelerating a = -0.5 m/s^2

0 = 2.0 m/s + (-0.5 m/s^2) * t

-2.0m/s = -0.5 m/s^2 * t

4 s = t

So time = 4 seconds

2007-03-17 10:40:37 · answer #1 · answered by Tony R 2 · 1 0

4seconds
explanation:
using formula v=u + at
u=2 v=0 a=-a(negative because astronaut is slowing down) t=t
therefore t=2/a
now use formula F=ma
F=100 m=200 a=a
therefore a=1/2
now put that back into t=2/a
therefore t=4

2007-03-17 18:12:32 · answer #2 · answered by multiplayertim 2 · 0 0

This has things to do with the gravitational forces and is not just Newtons law concepts. If it does not have the scope of the gravitation, escape velocity and all such crap then 4seconds might be the right answer.

2007-03-17 18:14:22 · answer #3 · answered by Pavan 3 · 0 0

Four seconds.

2007-03-17 17:37:28 · answer #4 · answered by Anonymous · 1 0

i am gonna lie i didn't know how to do this thank you for posting

2007-03-17 17:52:54 · answer #5 · answered by Praiser in the storm 5 · 0 0

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