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2 answers

Anything moving in a circular path experiences centripetal force

F = mv^2/r

here m = 1.0 kg, v = 5 m/s and r = 0.5 m

The centripetal force on the stone is hence 1*(5^2)/0.5 = 50 N

This is the tension that the string must support

2007-03-17 10:40:50 · answer #1 · answered by dudara 4 · 1 1

dudara is correct nothing to improve on his answer

2007-03-17 18:15:42 · answer #2 · answered by multiplayertim 2 · 0 0

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