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I want to check and see if I understand all of this correctly, so I'll list what I am thinking happens and you can correct me if I'm wrong, Ok?
I am talking about a very basic inductor in a very basic DC circuit, I am only wanting to understand the operation of an inductor in a circuit.

1. When the cirucit is first energized the coil acts like a resistor, it drops the maximum amount of voltage ( the amount of the source) which declines rapidly as the field builds. The voltage it drops is opposite to the increase in polarity only, equal in value.So it is exhibiting decreasing resistance to current flow in this charging state.

2 As current is decreased, the coil releases its energy by dropping a voltage of the same polarity to attempt and maintain the current's prior state. It is acting as a source in this state, but increasing its resistance to the change as its field deteriorates.
3. Steady state of current....NOT Sure?

2007-03-17 07:25:41 · 5 answers · asked by Anonymous in Science & Mathematics Physics

Steady STate - I am thinking now, there must be zero volt drop since htere is no change, so current will be maintained since it is not changing and no change in voltage drop or resistance ( reluctance) of the coil. Correct ?

2007-03-17 07:29:27 · update #1

5 answers

Your exactly right

the coil act like a resistor till the field builds

in steady state it can be presumed to have neglegable resistance

when voltage lowers it acts as a power source as the field colapses

a car's ignition coil is basically a simply inductor, it charges a magnetic field. to "FIRE" the coil you cut the power and the inductors field colapses all at once produceing a current to the spark plug.

2007-03-17 07:32:06 · answer #1 · answered by Justin H 4 · 0 0

Inductor Operation

2016-12-18 04:45:36 · answer #2 · answered by dalhaus 4 · 0 0

Part 1 & 2 are correct.

The steady state is what happens once the inductor is fully charged (or discharged depending on the action of the rest of the circuit).

For part 1 when the inductor reaches the steady state there will be zero resistance, and the current flow will be determined from the rest of the circuit.

For part 2 when the inductor reaches the steady state there is infinite resistance, and the current flow will be zero.

2007-03-17 07:32:44 · answer #3 · answered by Trevor B 3 · 0 0

in transient
the coil acts like a short circuit ( the resistance is omitted )

after the transient it acts like a currenr source that oppisite the true current

when the field collspse it will be just like a short circuit or a very small resistance

you must be very carful for example never plug a transformer - AC adapter for example - in DC voltage cuase it will be just like short circuiting the DC source and this dangerous

as for what you ask you will only need it if you study transient circuit behavior
for steady state in DC circuit you can treat the inductor as a short circuit or a very small resistance

NOTE:the inductor behaveor very differnt in AC circuir

2007-03-17 08:37:01 · answer #4 · answered by ? 3 · 0 0

had the same problem but found i just hadnt turned the plug on at the wall

2016-03-18 05:06:55 · answer #5 · answered by Anonymous · 0 0

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