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Solve:
(1/y) - (2/3) = (1/4)

2007-03-17 05:47:26 · 5 answers · asked by steph158_4 1 in Science & Mathematics Mathematics

5 answers

1/y - 2/3 = 1/4

1/y - 2/3 + 2/3 = 1/4 + 2/3

1/y = 1/4 + 2/3

12y(1/y) = 12y(1/4) + 12y(2/3)

12 = 3y + 8y

12y = 11y

12/11 = 11y/11

12/11 = y

Insert the y value into the equation

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Check

1y - 2/3 = 1/4

1/12/11 - 2/3 = 1/4

1/1 ÷ 12/11- 2/3 = 1/4

1/1 x 11/12 - 2/3 = 1/4

11/12 - 2/3 = 1/4

11/12 - 8/12 = 1/4

3/12 = 1/4

1/4 = 1/4
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2007-03-17 06:55:55 · answer #1 · answered by SAMUEL D 7 · 0 0

To solve for y:

(1/y) - (2/3) = (1/4)

Add (2/3) to both sides:

(1/y) = (1/4) + (2/3)

Find a common denominator for the fractions:

(1/y) = (1/4)*(3/3) + (2/3)*(4/4)
(1/y) = (3/12) + (8/12)

Add:

(1/y) = (11/12)

Multiply both sides by y:

1 = (11/12)y

Multiply both sides by the inverse of (11/12):

12/11 = y

2007-03-17 13:04:08 · answer #2 · answered by HallamFoe 4 · 0 0

First, add 2/3 to both sides...

1/y = 1/4 + 2/3

Then find a common denominator...

1/y = 3/12 + 8/12

Then add...

1/y = 11/12

Then take the reciprocal of each side

y = 12/11


The answer is 12/11

2007-03-17 13:03:58 · answer #3 · answered by Anonymous · 0 0

1/y - 2/3 = 1/4

First, add 2/3 to both sides...

1/y = 1/4 + 2/3

Then find a common denominator...

1/y = 3/12 + 8/12

Then add...

1/y = 11/12

Then take the reciprocal of each side (raise each side to the -1 power)...

y = 12/11
------------------------------
Check your work by plugging 12/11 in for y into the original equation:

1/(12/11) - 2/3

=11/12 - 2/3

= 11/12 - 8/12

= 3/12

= 1/4 All work is correct!

2007-03-17 13:00:27 · answer #4 · answered by Anonymous · 1 0

(1/y)-(2/3)=1/4
=> 12y*(1/y)-12y(2/3)=12y*1/4 [multiplying both sides by LCD 12y]
=>12-8y=3y
=> -8y-3y= -12
=> -11y= -12
=>y=12/11

2007-03-17 13:12:27 · answer #5 · answered by alpha 7 · 0 0

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