WX+YZ=WWW
In the addition problem shown above, W, X, Y, and Z represent nonzero digits. What is the value of Y?
2007-03-17 05:02:57 · 4 answers · asked by mubryan10 2 in Education & Reference ➔ Homework Help
If w,x,y,and z all represent digits then w has to equal 1 because you can't add 2 two digit numbers and get a number greater than 198. That makes
1X + YZ = 111
For this to work, X has to be at least 2 for YZ to be a 2 digit number. Now taking 111 - 12 all the way to 111 - 19 (111- all the numbers1X could be) this equals all numbers in the 90's.
This makes YZ = numbers from 99 to 92.
In any case Y is the first digit and is always 9.
Y = 9.
2007-03-17 06:10:40 · answer #1 · answered by Vinny G 2 · 0⤊ 0⤋
W=6, X=12, Y=36, Z=4
2007-03-17 05:50:57 · answer #2 · answered by sweetieface19 2 · 0⤊ 0⤋
WX+YZ =WWW
You just need to reorganize the equation:
1. Move WX to the right side (by substracting)
WX(-WX)+YZ=WWW(-WX)
YZ=WWW-WX
2. Then leave Y alone moving Z to the right (by dividing)
YZ/Z=(WWW-WX)/Z
Y=(WWW-WX)/Z
This would be your answer, you can simplify it more if you want:
Y= (W/Z)*(WW-X), but that is about it.
2007-03-17 05:18:12 · answer #3 · answered by Gaby 1 · 0⤊ 0⤋
Y = (www-wx)/ Z
2007-03-17 05:13:13 · answer #4 · answered by lynn y 3 · 0⤊ 0⤋