H2SO4 + Fe(OH)3 ----> Fe2(SO4)3 + H2O
2007-03-17 04:55:08 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
I would balance the equation as
3H2SO4 + 2Fe(OH)3 ------> Fe2(SO4)3 + 6H2O
Thereby making the number of hydrogen 12 on both sides
the number of sulfur becomes 3 on both sides
oxygen becomes 18 on both sides
iron becomes 2 on both sides and hydrogen becomes 12 on both sides. Balancing is all about making equal the amount of elements on both sides.
2007-03-17 05:15:19 · answer #1 · answered by Samuel_007 2 · 0⤊ 0⤋
3 H2SO4 + 2 Fe(OH)3 -----> Fe2(SO4)3 + 6 H2O
2007-03-17 12:04:58 · answer #2 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
As the sulfates are unchanged, treat them as another "element", for eg Z.
Now
H2Z + Fe(OH)3 -> Fe2Z3 + H2O
for every Fe on the right, you need two on the left
2H2Z + 2Fe(OH)3 -> Fe2Z3 + H2O.. and so on..
2007-03-17 11:59:23 · answer #3 · answered by Stephan B 5 · 0⤊ 1⤋
I wouldn't
Its St. Pats day
gonna get drunk and lucky maybe instead of doing Chem
2007-03-17 11:58:31 · answer #4 · answered by Anonymous · 0⤊ 1⤋
go to http://www.nitrogenorder.org/cgi-bin/balance.cgi to get all of your balancing problems correct...
2007-03-17 12:03:30 · answer #5 · answered by Austin T 2 · 0⤊ 1⤋