A traingle with side lengths in the ratio 3:4:5 is inscribed in a circle of radius 3. What is the area of the triangle???
Choices...
A)8.64
B)12
C)5 times pi
D)17.28
E)18
2007-03-17 03:02:34 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The only way the diameter can be the hypotenuse is if the triangle is a right triangle. it is, because 3^2+4^2=5^2. or 9+16=25, according to the Pythagorean theorem. So the hypotenuse is 6, because that is the diameter.
to find the legs you can just use the ratio you were given.
6/5 is 1.2, so multiply 3 and 4 by 1.2. so the length of the sides are 3.6, 4.8, and 6. the are would be (4.8*3.6)/2 which is 17.28.
so the answer is D.
2007-03-17 03:58:56 · answer #1 · answered by Rockachopa 1 · 0⤊ 0⤋
for a right triangle to exist inscribed in a circle, the hypotenuse is the diameter of the circle. Thus 6. This makes the legs equal to 24/5 and 18/5 respectively. 1/2 * 24/5 * 18/5 = 8.64
2007-03-17 10:31:01 · answer #2 · answered by Jeremy S 2 · 1⤊ 0⤋
Area of a triangle formula
A = 1/2 b h
A = 1/2 (3)(4)
A = 1/2(12)
A = 12 / 2
A = 6
- - - - - - - - - s-
2007-03-17 10:15:03 · answer #3 · answered by SAMUEL D 7 · 0⤊ 1⤋
b:12
2007-03-17 10:06:00 · answer #4 · answered by cheffunk2002 3 · 0⤊ 0⤋
the answer is 6..... its not even a choice u have on!
2007-03-17 10:37:34 · answer #5 · answered by Suzy J 2 · 0⤊ 1⤋
Do your own homework, you'll appreciate it next time.
2007-03-17 10:06:35 · answer #6 · answered by D 2 · 0⤊ 1⤋